Author: KermMartian
Posted: 31 Dec 2012 02:43:37 pm (GMT -5)
That is correct. Don't forget that 0v is pulling the link port bits to 1, and 5v is dropping them back to 0.
Reflection is a problem, but the serial lines are bi-directional, so you have a more immediate problem of immediately reading what you just wrote. That circuit you posted uses a very clever 555 system to avoid that problem.
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Posted: 31 Dec 2012 02:43:37 pm (GMT -5)
| ajcord wrote: | ||||
I don't need to receive any transmissions because DMX is entirely one-way.
So I would send a bit by pulling the ring either high or low depending if I want to send a high signal or a low signal. The tip would be for the input bit, which I don't need because I don't receive any data. Is that correct? |
| Quote: | ||
Do you mean that what I output would be fed back to the input bit? Possibly relevant is that the last DMX receiver on the line has a terminator to prevent the signal from being reflected and causing havoc. From what I understand, it's basically just a resistor that weakens the signal to the point that it's less than 0.2v and doesn't trigger a bit change. Would that prevent me from reading what I'm writing? |
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